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  > >y>>?>?>?>>y>>?>>t>>>>>?>>>?>>t>?>>?> > >  $ydodqfkh5dwhg 6fkrwwn\%duulhu'lrgh  0rgxoh $9  054=1       > > > > > > > > > > > > qa> > >? ?$???!?>>t? ? ????> > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > >>>>>>>>>>>>>>>>>>>>>>>>>>>>>> 8o> > % > >? ?? ??? ?? > 0> ? >??%???? *?}g=gwgg> > >?? ??> " )> ???? f?g3f?h?h?hlht3?7}> >?>y> >t???? ?? ??"?>>?? ?>>t??"????>???? ? ?? > ? >t>t> > >y>t>> ?> > 8o> > % > >? ?? ??? ?? > 0> ? >??%???? 2> > > >?????? ???? > a > >? ?$>>>t? ? ??> ?? ??!? " )> ???? 8p7v> >?>y> >???#? ??>>??!????? > >? > >> >e>?>?> ??>>y>t>b]> >?>> >> gbg?g=gcg?gf3?7?> > > > > > > >?>y> >?? ?>>??!???>>t??"????>>??#??> > >t>?> > ??>>t>b]>?> ?g>y>@?ho> ??>>t>b]>?> h/hmhqh=hnha> >?!???>???? ?>>y>@?ho> >y>>>> ?>  8k? ?(
v> > > > > >????? ? ???>>??!??? ???>??????? ? ?!??>>t? ???> ???# > h > >>>> hz> >>y>>b]> b]> ?? ?(
v> >?? ??? ??>??????? ? ?!??>>t? ??? > ??? ?> h > >>>> hz> >>y>>b]> b]> > ?$"i?> > >???? ???? ?>>??? ?? ?? ????? ???> > > > > > > > > > > > > > > > > > > > > > > > > > > > > > >>>>>>>> >>>>>>>>>>>>>>>>>>>>>>>>>> 8o> > % > >? ?? ??? ?? > 0?> >??%???? 2> > > >?????? ???? q`> >??> > 1?> ??%?> > q >? ?$> " ) ???? )~ gvgyg=> >??!?? ???> > ?????!? > ggg?gg4?> >??!?? ??? > >> >>> > > >y>>t> h > >y>>a> >g?? z'?4?> ??????? ?> > >y>>t> h > >y>>a> 2a5> ?????? > h > h > h > >t>> h > hc> > 7?$"i?> > >????? ???? ?>>??? ?? ?? ????? ???> 8o> > % > >? ?? ??? ?? > 0?> >??%???? 2> > > >?????? ???? q`> >??> > ? => ??%?> > q >? ?$> " ) ???? gbg?g=3?7v> >?>y> >?? ?>>t??"????>>??!????? > >? >t> > ??>>t>b]h? >t> >? >t>t> > h > >?>> >?>>> @?> gbg?g=8p7}> >?>y> >?? ?>>???#? ??>???? ? ??> ? >> > ??>>>t>b]h>? >> >>>?>>> h > >>>?>?> >>>?>? ?> !???> >?>y> ?????? ?>>t????? ? ???> >t ? ?>??>?>? k?4?>g?g?gg6?> >??!??? ???>? ?>>?? ??> h > h > >>>>a b]>?? >?>yhh g0g?gn\gft > ?? ??!?>>??>>y>>??>> 0g> >??!? ????>>e?? ?#???> g2w> >?????!?? >
> >y>>?>?>?>>y>>?>>t>>>>>?>>>?>>?>?>>?> > >      054=1    )lj  0 0.2 0.4 0.6 0.8 1 1.2 1 2 10 20 100 200 5 50 500 instantaneous forward voltage (v) %?8p7} >&>t instantaneous forward current (a) 8p7}"i? forward current vs. voltage (typical) tc =25c tc=150c %?  8p 7 v h>h pe r 1 a r m  )lj  0.001 0.01 0.1 1 0 200 400 600 800 1000 pulse width (s) ?y?? >&>q instantaneous forward current (a) %?8p7v>+?y?? instantaneous forward current vs. pulse width square pulse, non-repetitive, tc=25c (typical) %?  8p 7 v h>h pe r 1 a r m  )lj 0 20 40 60 80 100 120 0 20 40 60 80 100 average forward current (a) 1 ? 8p 7 v  >&>? average forward power dissipation (w) 1?8p7v??"i? average forward power dissipation >e>>y 1 ? 8p 7 ? ? ? h?h ? ? ? >e>? ?>?? >e>>>> >e>>>>t >e>>>>y >e>>>>> >??>>y>>??  )lj 0 25 50 75 100 125 150 0 20 40 60 80 100 120 case temperature ( b] ) ?? ?>&>' average forward current (a) 1?8p7v>+?? ?a average forward current vs. case temperature d=1 1 ? 8p 7 v h>h pe r 1 a r m ? ? ? >e > ? ?>? ? d=0.05 f>1khz d=0.5 d=0.2 d=0.1  )lj 1 10 100 1000 10 100 1000 10000 100000 pulse width ( @?? ) ?y??>&#v>' peak reverse power (w) ???3?7?>+?y?? peak reverse power vs. pulse width >???>>t>b]>? t+tnt3?7? pe r 1 a r m >??>? ? ? > >t >?>  )lj  25 50 75 100 125 150 0 0.2 0.4 0.6 0.8 1 1.2 1.4 case temperature ( b] ) ?? ?>&>' > >t>?>>>?? ?>?> >?>> >t>?>>>???>>t>b]>? ???3?7??a">+?? ? peak reverse power derating vs. case temperature t+tnt3?7??a" pe r 1 a r m 
> >y>>?>?>?>>y>>?>>t>>>>>?>>>?>>>?>>?> > >     054=1    )lj 0 20 40 60 80 100 120 140 0.001 0.003 0.01 0.03 0.1 0.3 1 3 10 30 100 300 1000 reverse voltage (v) 3?7} >&>t reverse leakage current (ma) ??7v>+3?7} reverse leakage current vs. reverse voltage (typical) tc=25c tc=150c ? g 7 v h?>h per 1 arm tc=75c tc=125c  )lj  >y> >>a >y> >> >y> >> >y> >>? >y> >>t >y> >>y >y >>>>>y >>>>y >>>y >y >y> >???!? ??>>>?!???>>>e?!?? ? ???>>>??>? f6?f>??>? >???? ???&??>>??? ?????? >>?????? ?>>>?????? ??? ??? ? >?>?>>?>? >?>t? ?> >?>?>>?>? ? >>>?b]>??>? 4#f?f!?f?f?f"if? >? ?$???!?>>??? ?????? >>?????? ?>>>?????? ??? >>>g >>>0d >>> > f4# >f? >f!? >f? >f? hb]>??h pe r 1 a r m        >?>?>e> ?!???> >t? ?>??>?>?>>>>>a>>?b]>??>?> uwk -& 
? outline drawing      054=1 


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